Handout #8 Markov Chains
Suppose
there is a random sequence, X, such that:
X = {a, b,
�, N }
That
corresponds to a time interval [0, t].
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X = { |
a, |
b, |
�, |
N } |
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� |
� |
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� |
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So,
Xt=0 = X0
= ����������������
Xt=1 = X1
= ����������������
M
Xt=t = Xt
= �����������������
[Note:� The values that Xt
take on are finite or countably infinite.]
Then,
the Markov Chain Property is:
P[Xt-1 = j | X0
= a, X1 = b, K, Xt
= i ] = P[Xt-1 = j | Xt
= i ] = qij ( t
)
= the conditional
probability that the Markov Chain is at time t in state j,
given that at time (t-1) it was
in state i.
qij ( t ) is also called the
transition probability
What
does this mean?
P [ future states | past & present states ] is independent
of the past events and depends only on the present state of the probability pj( t + 1 ) {which represents the random value Xt+1
takes on in state j}.
Or,
in matrix and vector representation,
p( t + 1 ) = p( t ) Q( t )
where,
p( t ) is an N-dimensional row
vector with elements pj( t ), for j = 1,
2, �, N
Q( t ) is an N x N matrix with
the elements qij( t ) and is called the
Markov transition probability matrix at time t.
Stationary
or Homogeneous
If
all qij( t ) are independent of time t, then,
p( t + 1 ) = p( t ) Q
Q
and Q( t ) must follow the properties:
qij( t ) � 0, for all i, j
and t = 0, 1, 2, �
Example:� State Transition Diagram, page 83 of handout
States:� { 1, 2, 3 }
Transitions:
q12 = 1, q23 = 1/2, q33
= 1/2, q32 = 1/2, q22 = 1/4, q21 = 1/4
So,
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q11 |
q12 |
q13 |
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Q
= |
q21 |
q22 |
q23 |
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q31 |
q32 |
q33 |
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Q
= |
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Nonstationary:
p( t ) = p( 0 ) Q( 0 ) Q( 1
) � Q( t � 1 )
Stationary:
p( t ) = p( 0 ) Qt
If
we let t = s + n, then:
p( s + n ) = p( 0 ) Qs
Qn = p( s ) Qn
Then,
From
magic, we end up with:
P( z ) = p( 0 ) [ I � Qz ]-1, where I is the identity matrix
Asymptotic
Behavior:
length of time = "first passage of time"
(in terms of number of transitions)
when i = j
length of time = "recurrence time" for state i
Let
be the probability that the first passage time from state i to state j is equal to n.
Then,
is
the probability that starting in state i, the system
reaches state j.
If:
fij �������������������� :� may
never reach j
fij �������������������� :�
probability distribution of the first passage of time
If i = j, �is the probability
that starting in state i, system reaches state j (so
if i = j, system gets back to i).
If:
fii �������������������� :�
transient state
fii �������������������� :�
recurrent state � probability distribution of recurrence time
Since
they are just probability distributions, then we know they have mean values!
So,
whenever fij = 1,
Look
at Figure 2.10.
Difficult
to find
|
i |
j |
n = |
1 |
2 |
3 |
4� |
|
1 |
1 |
|
0 |
1(1/4)
= �� |
1(1/4)(1/4)
= |
� |
The
mean though is easy to find:
etc.
When
j = i,� mii = expected recurrence time
If:
mii ������������������ , then recurrent state i
is a null-recurrent state
mii ������������������ , then recurrent state i
is a positive-recurrent state or regular-recurrent state
Periodic state:� A state is periodic if n/t is
not integer divisible (t is the greatest integer with this property) and ��In other words, a
return to state i is impossible unless it occurs in
t, 2t, 3t,� steps.
Ergodic state:� A state that is neither null nor periodic.
Absorbing state:� A state where once in, one can never leave.
Reachable state: , for n � 1.� If a state is reachable, then the state can
communicate.
If
all states in a state diagram can communicate, then the chain is irreducible.
So
(page 88)
�
States of an irreducible chain are either all recurrent or all
transient.
�
If one is periodic with period t, then all states are periodic with
period t.
Question:� Does a system converge to some limiting
distribution?
Assume
an aperiodic, irreducible system is stable.� Let,
Then,
by page 83,
p( t + 1 ) = p( t ) Q
p = p Q
A
probability distribution p satisfying this equation is
called a stationary distribution.� See
Theorem 2.9.2., page 89.
An
irreducible aperiodic Markov Chain has:
�
At most one stationary distribution
�
And either
1.
All states are transient or all are null, so there's no stationary
distribution.
2.
All states are ergodic, so there's a unique
stationary distribution.